Part A Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Rate law: k[H]^2 k= 6.4*10^-9 (mol*s) at 500 K Initial rate = 1.6...

60.1K

Verified Solution

Question

Chemistry

Part A

Consider the second-order reaction:

2HI(g)→H2(g)+I2(g)

Rate law: k[H]^2

k= 6.4*10^-9 (mol*s) at 500 K

Initial rate = 1.6 * 10^-7 mol (l*s)

What will be the concentration of HI after t =3.65×1010 s ([HI]t) for a reaction startingunder this condition?

Part B

In a study of the decomposition of the compound X via thereaction

X(g)⇌Y(g)+Z(g)

the following concentration-time data were collected:

Time (min)[X](M)
00.467
10.267
20.187
30.144
40.117
50.099
60.085
70.075

Given that the rate constant for the decomposition ofhypothetical compound X from part A is 1.60 M−1⋅min−1,calculate the concentration of X after 14.0 min .

Part C

The following data were collected for the rate of disappearanceof NO in the reaction2NO(g)+O2(g)→2NO2(g):

Experiment[NO](M)[O2](M)Initial Rate (M/s)
10.01260.01251.41×10−2
20.02520.02501.13×10−1
30.02520.01255.64×10−2

What is the rate of disappearance of NO when [NO]=6.15×10−2 M and [O2]=1.75×10−2 M ?

Part D

What is the rate of disappearance of O2 at the concentrationsgiven in part (c)?

Part E

A certain reaction with an activation energy of 175 kJ/mol wasrun at 515 K and again at 535 K . What is the ratio of fat the higher temperature to f at the lowertemperature?

Usef=e^−Ea/(R⋅T)

Answer & Explanation Solved by verified expert
4.2 Ratings (524 Votes)
Part A given rateKHI2 If initial rate16107 mol L s then HIoinitial concentration initial rateK12 sqrt 16107 mol L s64109 Lmol S50 molL using rate equation for second order Kt1HIo1HIt 64109 Lmol S 3651010 s150 molL1HIt solving    See Answer
Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students