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Part A A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate...

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Chemistry

Part A

A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with0.500 M HNO3. Calculate the pH after the addition of 25.0 mL ofHNO3.

Part B

A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10−5) is titratedwith 0.40 M NaOH. Calculate the pH after the addition of 21.0 mL ofNaOH.

Answer & Explanation Solved by verified expert
4.3 Ratings (770 Votes)
A Initial moles of NH3 751000 X 0200 0015 mol Moles of HNO3 added 251000 X 0500 00125 mol NH3 HNO3 NH4 NO3 Moles of NH3 left 0015 00125 00025 mol Moles    See Answer
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