Part A A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH. Calculate the...

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Chemistry

Part A

A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH.Calculate the pH after the addition of 18.0 mL of KOH.

Part B

A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5)is titrated with 0.500 M HNO3. Calculate the pH after theaddition of 13.0 mL of HNO3.

Part A

A 52.0-mL volume of 0.35 M CH3COOH(Ka=1.8×10−5) is titrated with 0.40 M NaOH.Calculate the pH after the addition of 25.0 mL of NaOH.

Answer & Explanation Solved by verified expert
3.6 Ratings (387 Votes)
A Given MHBr 025 M VHBr 50 mL MKOH 025 M VKOH 18 mL molHBr MHBr VHBr molHBr 025 M 50 mL 125 mmol molKOH MKOH VKOH molKOH 025 M 18 mL 45 mmol We have molHBr 125 mmol molKOH 45 mmol 45 mmol of both will react remaining mol of HBr 8 mmol Total volume 680 mL H mol of acid    See Answer
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