Part 1: Calculate the solubility (in M) of cobalt(II) hydroxide, Co(OH)2(s) in H2O. Ksp = 2.80Ã—10-16...

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Part 1: Calculate the solubility (in M) of cobalt(II)hydroxide, Co(OH)2(s) in H2O. Ksp = 2.80Ã—10-16 ata specific temperature
Part 2; What is the pH of this solution of cobalt(II)hydroxide?

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3.6 Ratings (508 Votes)

part1

Co(OH)2(s) ---------------> Ca^2+ (aq) + 2OH^- (aq)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2x

KspÂ Â Â = [Co^2+][OH^-]^2

2.8*10^-16Â Â = x*(2x)^2

2.8*10^-16Â Â = 4x^3

x^3Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 7*10^-17

xÂ Â = 4.12*10^-6

solubility of Co(OH)2 in water = 4.12*10^-6M

part-b

Co(OH)2(s) ---------------> Ca^2+ (aq) + 2OH^- (aq)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2x

KspÂ Â Â = [Co^2+][OH^-]^2

2.8*10^-16Â Â = x*(2x)^2

2.8*10^-16Â Â = 4x^3

x^3Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 7*10^-17

xÂ Â = 4.12*10^-6

[OH^-]Â Â = 2x = 2*4.12*10^-6

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 8.24*10^-6M

POHÂ Â = -log[OH^-]

Â Â Â Â Â Â Â Â Â Â Â = -log8.24*10^-6

Â Â Â Â Â Â Â Â Â Â Â Â Â =5.084

PHÂ Â = 14-POH

Â Â Â Â Â Â Â Â Â = 14-5.084

Â Â Â Â Â Â Â Â Â = 8.916>>>>answer

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