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Out of several months of data, Tony's Timepieces has isolated the highest and lowest monthly levels of activity for their repair services The highest is 310 hours for the month and the lowest is 180 hours. The cost corresponding to the highest activity is 16, 600 and the cost related to the lowest activity is 11,600 cost. Based on these dat: points what is the fixed costs of operating between the lowest and highest levels of activity? ( In other words what is the intercept determined from using the high-low method?) ou Answered brrect Answer 4,677 margin of error +/- 1% Out of several months of data, Tony's Timepieces has isolated the highest and lowest monthly levels of activity for their repair services The highest is 310 hours for the month and the lowest is 180 hours. The cost corresponding to the highest activity is 16, 900 and the cost related to the lowest activity is 11,500 cost. Based on these data points, use high low to determine a cost equation and the provide an estimate the cost of 250 hours based on that cost equation. You Answered Correct Answer 14,408 margin of error +-4 Out of several months of data, Tony's Timepieces has isolated the highest and lowest monthly levels of activity for their repair services The highest is 320 hours for the month and the lowest is 180 hours. The cost corresponding to the highest activity is 16, 600 and the cost related to the lowest activity is 11,200 cost. Based on these data points what is the variable cost per hour (use 2 decimal places) of operating between the lowest and highest levels of activity? ( In other words what is the slope determined from using the high-low method?) You Answered Correct Answer 38.57 margin of error +/- 0.01

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