Once the stock solutions are prepared, describe how you would produce your buffers (four). Your explanation...

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Chemistry

Once the stock solutions are prepared, describe how you wouldproduce your buffers (four). Your explanation should be detailedand quantitative.
For my stock solution:
KH2PO4 = (136.08 g/mol)(1M)(100.00ml/1000ml)= 13.608 gm
Â Â Â Â Â Â Â Â Â Â Â K2HPO4 = (174.17 g/mol)(1M)(100.00ml/1000ml)= 17.4178 gm
KH2PO4= (136.08 g/mol)(1M)(250.00ml/1000ml)= 34.02 gm
K2HPO4= (174.17 g/mol)(1M)(250.00ml/1000ml)= 43.54 gm
Â Â Â Â Â Â Â Â Â Â Â KH2PO4= (136.08 g/mol)(1M)(25.00ml/1000ml) = 3.402 gm
Â Â Â Â Â Â Â Â Â Â Â K2HPO4= (174.17 g/mol)(1M)(25.00ml/1000ml) = 4.35425 gm
KH2PO4= (136.08 g/mol)(1M)(10.00ml/1000ml)= 1.3608 gm
K2HPO4= (174.17 g/mol)(1M)(10.00ml/1000ml)= 1.74178 gm
Â Â Â Â Â Â Â Â Â Â Â KH2PO4= (136.08 g/mol)(1M)(5.00ml/1000ml)= 0.6804 gm
Â Â Â Â Â Â Â Â Â Â Â K2HPO4= (174.17 g/mol)(1M)(5.00ml/1000ml)= 0.87085 gm

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4.2 Ratings (780 Votes)

For my stock solution KH2PO4 13608 gmol1M10000ml1000ml 13608 gm This information means that you prepare 100 mL of 1 M solution Fill about half with water an 100 mL volumetric flask dissolve the calculated mass of substance See Answer

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