Now try a different way of solving a dihybrid cross. Because of Mendel's (second) law...

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Now try a different way of solving a dihybrid cross. Because of Mendel's (second) law of independent assortment, you can work with the blood type gene and the hemoglobin gene separately. Set up two monohybrid crosses with the following parents: the mother is heterozygous for type B blood and has sickle cell trait, while the father has type AB blood and also has sickle cell trait. a. What are the chances that a child of this couple will have type B blood and sickle cell trait?b. What are the chances that a child will have type AB blood and will not have sickle cell disease? c. What are the chances that a child will have type B blood and sickle cell disease? d. What are the chances that a child will have type B blood and at least some normal hemoglobin? (Show your work.)

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