pKb = 5.68
Kb = 2.089 x 10^-6
C4H9NO + H2O ---------------------->Â Â HC4H9NO+
+Â Â OH-
0.011Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0
0.011-x                                                          Â
x              Â
x
Kb = x^2 / 0.011 - x
2.089 x 10^-6 = x^2 / 0.011 - x
x = 1.506 x 10^-4
[OH-] = 1.51 x 10^-4 M
[ HC4H9NO+] = 1.51 x 10^-4
M
[C4H9NO] = 0.0108 M
[H3O+] = 6.61 x 10^-11 M
pOH = -log [OH-] = -log (1.506 x 10^-4)
       = 3.82
pH = 10.18
