Morpholine (C4H9NO) is a weak organic base with pKb=5.68. Calculate the pH in a 1.10Ã—10âˆ’2M morpholine solution. Calculate the...

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Morpholine (C4H9NO) is a weak organic base withpKb=5.68.
Calculate the pH in a 1.10Ã—10^âˆ’2M morpholinesolution.
Calculate the the concentration of C4H9NO in a1.10Ã—10^âˆ’2M morpholine solution.
Calculate the the concentration of HC4H9NO+ in a1.10Ã—10^âˆ’2M morpholine solution.
Calculate the concentration of H3O+ in a1.10Ã—10^âˆ’2M morpholine solution.
Calculate the concentration of OHâˆ’ in a1.10Ã—10^âˆ’2M morpholine solution.
Please show work thank you!

Answer & Explanation Solved by verified expert

4.0 Ratings (616 Votes)

pKb = 5.68

Kb = 2.089 x 10^-6

C4H9NO + H2O ---------------------->Â Â HC4H9NO+ +Â Â OH-

0.011Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0

0.011-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â x

Kb = x^2 / 0.011 - x

2.089 x 10^-6 = x^2 / 0.011 - x

x = 1.506 x 10^-4

[OH-] = 1.51 x 10^-4 M

[ HC4H9NO+] = 1.51 x 10^-4 M

[C4H9NO] = 0.0108 M

[H3O+] = 6.61 x 10^-11 M

pOH = -log [OH-] = -log (1.506 x 10^-4)

Â Â Â Â Â Â Â = 3.82

pH = 10.18

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