Molarity of standard NaOH solution: x/1 H 2/3 Unknown + 2/3 NaOH -> 2/3 H2O +Na...

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Chemistry

Molarity of standard NaOH solution: x/1 H 2/3 Unknown + 2/3 NaOH-> 2/3 H2O +Na 2/3 Acetate
Vinegar: Titration 1 Titration 2 Tirtration 3
Initial V of Acid .01 mL 5.56 mL 11.32 mL
Final V of Acid 5.56 mL 10.71 mL 16.02 mL
Inital V of Base .01 mL 27.12 mL 3.01 mL
Final V of Base 22.23 mL 44.71 mL 24.90 mL
Unknown Acid code and number of reactive hydrogens: H+3
Unknown Acid Titration 1 Titration 2 (Error) Titration 3 Titration 4
Mass of Acid .1024 g .1028g .1021g .1023g
Initial V of Base 24.90 mL 37.80 mL 45.5 mL 9.24 mL
Final V of Base 37.80 mL 45.5 mL 9.24 mL 17.80 mL
4. Find the molarity of the vinegar for each of your threevinegar titrations, then find the average molarity of the acid.
5. Find the percent deviations for your three vinegar molaritiesfor the vinegar titrations.
6. From the moles of acetic acid for each vinegar titration,find the mass of acetic acid for that titration

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3.7 Ratings (418 Votes)

Vinegar Titration 1 Titration 2 Tirtration 3 1 Initial V of Acid 01 mL 556 mL 1132 mL 2 V of Acid 556 mL 1071 mL 1602 mL 3Inital V of Base 01 mL 2712 mL 301 mL See Answer

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Vinegar:	Titration 1	Titration 2	Tirtration 3
Initial V of Acid	.01 mL	5.56 mL	11.32 mL
Final V of Acid	5.56 mL	10.71 mL	16.02 mL
Inital V of Base	.01 mL	27.12 mL	3.01 mL
Final V of Base	22.23 mL	44.71 mL	24.90 mL

Unknown Acid	Titration 1	Titration 2 (Error)	Titration 3	Titration 4
Mass of Acid	.1024 g	.1028g	.1021g	.1023g
Initial V of Base	24.90 mL	37.80 mL	45.5 mL	9.24 mL
Final V of Base	37.80 mL	45.5 mL	9.24 mL	17.80 mL