Molarity of NaOH solution: .25 M 1. Trial Titration Final buret volume (mL): 34.4 mL Initial Buret Volume...

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Chemistry

Molarity of NaOH solution: .25 M
1. Trial Titration
Final buret volume (mL): 34.4 mL
Initial Buret Volume (mL): 0mL
Volume of NaOH solution (mL): 34.4 mL
2. Exact titration
Sample no. 1 2 3 4
Final buret volume (mL)36.1, 34.9, 34.2, 46.2
intial buret buret volume (mL) 0, 0, 0, 12
Volume of NaOH solution (mL) 36.1, 34.9, 34.2, 34.2
concentration of HC2H3O2 (M) ______
Mean Concentration (M) _ _____
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Questions:
1.The manufacture of the vnegar used in this experiment claimsthat the vinegar contains 5% acedic acid by weight. use yourresults and a density of 1.0 g/ml to determin of this claim is trueor false

Answer & Explanation Solved by verified expert

4.4 Ratings (941 Votes)

1 M NaOH 40 GMS IN 1000 ML or 4 gms in 100 or 04 in 10 ml THEREFORE 025 M NaOH0254010110 gms NaOH Required FOR 1000 ML 1Trail Titration INITIAL READING0 MLfinal reading NaOH344 ML 344 ML REQUIRED TO TITRATE ACETIC ACID Now we can calculate the actual moles of NaOH FROM 344 ML 25 M CONC 1000 ML 10 GMS THEN 344 ML BY CROSS MULTIPLYING See Answer

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