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Menthanol, CH3OH, formally know as wood alcohol is manufacutred commercially by the following reaction: CO (g)...

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Chemistry

Menthanol, CH3OH, formally know as wood alcohol is manufacutredcommercially by the following reaction: CO (g) + 2H2 (g) -->CH3OH (g) a 1.5000 -L vessel was filled with 0.1500 mol CO and0.3000 mol H2. When this mixture came to equlilbrium at 500K, thevessel contained 0.1187 mol CO. How many coles of each substancewere in the vessel?

Part 2. Obtain the vaule of Kc for the following reaction at500K

CO (g) + 2H2 (g) --> CH3OH (g) Use the data calculatedabove.

please show work. thanks

Answer & Explanation Solved by verified expert
3.7 Ratings (701 Votes)

PArt A :

The reaction is

       CO (g)       +          2H2 (g)     -->     CH3OH (g)

Initial                      0.15 / 1.5              0.3 / 1.5             0

Change              -x                             -2x                      x

Equilibrium           0.1-x                       0.2-2x                x

Given x = 0.1187

So moles of CO = 0.15-0.1187 = 0.0313

Moles of H2 = 0.3 - 2X0.1187 = 0.0626

Moles of CH3OH = 0.1187

Part 2

Kc = [CH3OH] / [CO][H2]2

Kc = 0.1187 / 0.0313 X (0.0626)2

Kc = 967.73
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