M, a solid cylinder (M=1.83 kg, R=0.117 m) pivots on a thin,fixed, frictionless bearing. A string wrapped around the cylinderpulls downward with a force F which equals the weight of a 0.690 kgmass, i.e., F = 6.769 N. Calculate the angular acceleration of thecylinder. Because the bearing is thin, the moment of inertia of thebearing is essentially that of a solid cylinder
If instead of the force F an actual mass m = 0.690 kg is hungfrom the string, find the angular acceleration of the cylinder.
How far does m travel downward between 0.490 s and 0.690 s afterthe motion begins?
The cylinder is changed to one with the same mass and radius,but a different moment of inertia. Starting from rest, the mass nowmoves a distance 0.496 m in a time of 0.550 s. Find Icm of the newcylinder.
