M, a solid cylinder (M=1.35 kg, R=0.117 m) pivots on a thin, fixed, frictionless bearing. A...

50.1K

Verified Solution

Question

Physics

M, a solid cylinder (M=1.35 kg, R=0.117 m) pivots on a thin,fixed, frictionless bearing. A string wrapped around the cylinderpulls downward with a force F which equals the weight of a 0.670 kgmass, i.e., F = 6.573 N. Calculate the angular acceleration of thecylinder. Tries 0/10 If instead of the force F an actual mass m =0.670 kg is hung from the string, find the angular acceleration ofthe cylinder. Tries 0/10 How far does m travel downward between0.450 s and 0.650 s after the motion begins? Tries 0/10 Thecylinder is changed to one with the same mass and radius, but adifferent moment of inertia. Starting from rest, the mass now movesa distance 0.470 m in a time of 0.510 s. Find Icm of the newcylinder.

Answer & Explanation Solved by verified expert

3.9 Ratings (649 Votes)

Moment of inertia for a solid disk I mr22 A Sum of the moments about the center of the disk Ialpha Fr Sub in I mr22 mr22 alpha Fr mr 2 alpha F Solve for alpha alpha 2F mr Plug in numbers alpha 2 6573 N 135 kg 117 m 8325 rads2 B Same thing becuase in the See Answer

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member