Listed below are systolic blood pressure measurements​ (mm Hg)taken from the right and left arms of the same woman. Assume thatthe paired sample data is a simple random sample and that thedifferences have a distribution that is approximately normal. Use a0.100.10 significance level to test for a difference between themeasurements from the two arms. What can be​ concluded? Right arm148148 133133 142142 130130 131131 Left arm 182182 164164 176176149149 134134 In this​ example, mu Subscript dμd is the mean valueof the differences d for the population of all pairs of​ data,where each individual difference d is defined as the measurementfrom the right arm minus the measurement from the left arm. Whatare the null and alternative hypotheses for the hypothesis​ test?A. Upper H 0H0​: mu Subscript dμdnot equals≠0 Upper H 1H1​: muSubscript dμdgreater than>0 B. Upper H 0H0​: mu Subscriptdμdequals=0 Upper H 1H1​: mu Subscript dμdless than<0 C. Upper H0H0​: mu Subscript dμdequals=0 Upper H 1H1​: mu Subscript dμdnotequals≠0 D. Upper H 0H0​: mu Subscript dμdnot equals≠0 Upper H1H1​: mu Subscript dμdequals=0 Identify the test statistic.tequals=nothing ​(Round to two decimal places as​ needed.) Identifythe​ P-value. ​P-valueequals=nothing ​(Round to three decimalplaces as​ needed.) What is the conclusion based on the hypothesis​test? Since the​ P-value is ▼ greater less than the significance​level, ▼ reject fail to reject the null hypothesis. There ▼ is notis sufficient evidence to support the claim of a difference inmeasurements between the two arms.