Let {z0, z1, z2, . . . , z2017} be the solution set of the
equation...
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Let {z0, z1, z2, . . . , z2017} be the solution set of theequation z^2018 = 1. Show that z0 +z1 +z2 +···+z2017 = 0.
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Consider the number z0 exp2pii5 This is one of the five fifthroots of unity These five roots lie on the unit circle in the complex plane equally spaced and have the form z0 z02 z03 z04 1 t is the similarity of these roots to the terms in the zpolynomial that gives us a clue as to how to
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