Let x represent the number of mountain climbers killedeach year. The long-term variance of x is approximatelyσ2 = 136.2. Suppose that for the past 6 years,the variance has been s2 = 107.1. Use a 1%level of significance to test the claim that the recent variancefor number of mountain-climber deaths is less than 136.2. Find a90% confidence interval for the population variance.
(a) What is the level of significance?
State the null and alternate hypotheses.
Ho: σ2 = 136.2;H1: σ2 >136.2Ho: σ2 < 136.2;H1: σ2 =136.2    Ho:σ2 = 136.2; H1:σ2 ≠136.2Ho:σ2 = 136.2; H1:σ2 < 136.2
(b) Find the value of the chi-square statistic for the sample.(Round your answer to two decimal places.)
What are the degrees of freedom?
What assumptions are you making about the originaldistribution?
We assume a uniform population distribution.We assume aexponential population distribution.    Weassume a binomial population distribution.We assume a normalpopulation distribution.
(c) Find or estimate the P-value of the sample teststatistic.
P-value > 0.1000.050 < P-value <0.100Â Â Â Â 0.025 < P-value <0.0500.010 < P-value < 0.0250.005 <P-value < 0.010P-value < 0.005
(d) Based on your answers in parts (a) to (c), will you reject orfail to reject the null hypothesis?
Since the P-value > α, we fail to rejectthe null hypothesis.Since the P-value > α, wereject the null hypothesis.    Since theP-value ≤ α, we reject the null hypothesis.Sincethe P-value ≤ α, we fail to reject the nullhypothesis.
(e) Interpret your conclusion in the context of theapplication.
At the 1% level of significance, there is insufficient evidenceto conclude that the variance for number of mountain climber deathsis less than 136.2At the 1% level of significance, there issufficient evidence to conclude that the variance for number ofmountain climber deaths is less than136.2Â Â Â Â
(f) Find the requested confidence interval for the populationvariance. (Round your answers to two decimal places.)
lower limit | |
upper limit    | |
Interpret the results in the context of the application.
We are 90% confident that σ2 lies above thisinterval.We are 90% confident that σ2 lieswithin this interval.    We are 90% confidentthat σ2 lies outside this interval.We are 90%confident that σ2 lies below this interval.