Let x be a random variable that represents white blood cell count per cubic milliliter of...

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Let x be a random variable that represents white bloodcell count per cubic milliliter of whole blood. Assume thatx has a distribution that is approximately normal, withmean μ = 6150and estimated standard deviation σ =2200. A test result of x < 3500 is an indication ofleukopenia. This indicates bone marrow depression that may be theresult of a viral infection.

(a) What is the probability that, on a single test, xis less than 3500? (Round your answer to four decimalplaces.)


(b) Suppose a doctor uses the average x for two teststaken about a week apart. What can we say about the probabilitydistribution of x?

The probability distribution of x is not normal.Theprobability distribution of x is approximately normal withμx = 6150 andσx =1555.63.     The probability distributionof x is approximately normal withμx = 6150 andσx = 2200.The probability distributionof x is approximately normal withμx = 6150 andσx = 1100.00.


What is the probability of x < 3500? (Round your answerto four decimal places.)


(c) Repeat part (b) for n = 3 tests taken a week apart.(Round your answer to four decimal places.)


(d) Compare your answers to parts (a), (b), and (c). How did theprobabilities change as n increased?

The probabilities decreased as n increased.Theprobabilities increased as nincreased.     The probabilities stayedthe same as n increased.


If a person had x < 3500 based on three tests, whatconclusion would you draw as a doctor or a nurse?

It would be an extremely rare event for a person to have two orthree tests below 3,500 purely by chance. The person probably hasleukopenia.It would be a common event for a person to have two orthree tests below 3,500 purely by chance. The person probably doesnot have leukopenia.     It would be acommon event for a person to have two or three tests below 3,500purely by chance. The person probably has leukopenia.It would be anextremely rare event for a person to have two or three tests below3,500 purely by chance. The person probably does not haveleukopenia.

Answer & Explanation Solved by verified expert
3.8 Ratings (516 Votes)
GivenIt is given that white blood cell counts are approximatelynormally distributeda Px 3500Since it is given that theFor the given values Z is calculated as below since it isnormally distributedHence the given sample size is 1 n 1 Therefore the z valuefor x 3500 is given asHence PX 3500 PZ 12045 The probability valuecan be estinmated from the standard normal distribution using Excelwith    See Answer
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