Let X and Y be independent Exponential random variables with common mean 1. Their joint pdf is...

50.1K

Verified Solution

Question

Basic Math

Let X and Y be independent Exponential random variables withcommon mean 1.

Their joint pdf is f(x,y) = exp (-x-y) for x > 0 and y > 0, f(x, y ) = 0 otherwise. (See "Independence" on page 349)

Let U = min(X, Y) and V = max (X, Y).

The joint pdf of U and V is f(u, v) = 2 exp (-u-v) for 0 < u< v < infinity, f(u, v ) = 0 otherwise. WORDS: f(u, v ) istwice f(x, y) above the diagonal in the first quadrant, otherwisef(u, v ) is zero.

(a). Use the "Marginals" formula on page 349 to get the marginalpdf f(u) of U from joint pdf f(u, v) HINT: You should know theanswer before you plug into the formula.

(b) Use the "Marginals" formula on page 349 to get the marginalpdf f(v) of V from joint pdf f(u, v) HINT: You found f(v) in aprevious HW by finding the CDF of V. You can also figure out theanswer by thinking about two independent light bulbs and adding theprobabilities of the two ways that V can fall into a tiny intervaldv.

(c) Find the conditional pdf of V, given that U = 2. (See page411). HINT: You can figure out what the answer has to be bythinking about two independent light bulbs and remembering thememoryless property.

(d) Find P( V > 3 | U= 2 ). (See bottom of page 411. Do theappropriate integral, but you should know what the answer willbe.)

(e) Find the conditional pdf of U, given that V = 1. (See page411).

(f) Find P ( U < 0.5 | V = 1).

HINT: You should know ahead of time whether the answer is >or < or = 1/2.

Answer & Explanation Solved by verified expert
3.6 Ratings (488 Votes)
    See Answer
Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students