Let x = age in years of a rural Quebec woman at thetime of her first marriage. In the year 1941, the populationvariance of x was approximately σ2 =5.1. Suppose a recent study of age at first marriage for a randomsample of 31 women in rural Quebec gave a sample variances2 = 2.7. Use a 5% level of significance totest the claim that the current variance is less than 5.1. Find a90% confidence interval for the population variance.
(a) What is the level of significance?
State the null and alternate hypotheses.
Ho: σ2 = 5.1;H1: σ2 ≠5.1
Ho: σ2 = 5.1;H1: σ2 <5.1 Â
Ho: σ2 < 5.1;H1: σ2 = 5.1
Ho: σ2 = 5.1;H1: σ2 > 5.1
(b) Find the value of the chi-square statistic for the sample.(Round your answer to two decimal places.)
What are the degrees of freedom?
What assumptions are you making about the originaldistribution?
We assume a binomial population distribution.We assume a normalpopulation distribution.    We assume a uniformpopulation distribution.We assume a exponential populationdistribution.
(c) Find or estimate the P-value of the sample teststatistic.
P-value > 0.100
0.050 < P-value <0.100Â Â Â Â 0.025 < P-value <0.050
0.010 < P-value < 0.025
0.005 < P-value < 0.010
P-value < 0.005
(d) Based on your answers in parts (a) to (c), will you reject orfail to reject the null hypothesis?
Since the P-value > α, we fail to rejectthe null hypothesis.
Since the P-value > α, we reject the nullhypothesis.  Â
Since the P-value ≤ α, we reject the nullhypothesis.
Since the P-value ≤ α, we fail to reject thenull hypothesis.
(e) Interpret your conclusion in the context of theapplication.
At the 5% level of significance, there is insufficient evidenceto conclude that the variance of age at first marriage is less than5.1.
At the 5% level of significance, there is sufficient evidence toconclude that the that the variance of age at first marriage isless than 5.1.   Â
(f) Find the requested confidence interval for the populationvariance. (Round your answers to two decimal places.)
lower limit | |
upper limit    | |
Interpret the results in the context of the application.
We are 90% confident that σ2 lies above thisinterval.
We are 90% confident that σ2 lies withinthis interval.   Â
We are 90% confident that σ2 lies below thisinterval.
We are 90% confident that σ2 lies outsidethis interval.