0.001% means 0.001 g of Pb in 100g of H2O
1 g of Pb present in (100/0.001 )*1 = 10^5 g of
H2O
145 mg of Pb present in 10^5 * 145 * 10^-3
g
                                          Â
= 14500 g of water
                                         Â
= 1.45 * 10^4 g of H2O
since density = 1 g /mL then
      Â
                                Â
= 1.4 * 10^4 mL of H2O (2 significants)
