Jeffrey Mitton and his colleagues found three genotypes (R2R2, R2R3, and R3R3) at a locus encoding...

Free

90.2K

Verified Solution

Question

Biology

Jeffrey Mitton and his colleagues found three genotypes (R2R2,R2R3, and R3R3) at a locus encoding the enzyme peroxidase inponderosa pine trees growing at Glacier Lake, Colorado. Theobserved numbers of these genotypes were: Genotypes: Numberobserved: R2R2 135 R2R3 44 R3R3 11 a. Determine the allelefrequencies for the R2 and R3 alleles. b. Use the Chi square testto determine if this population is in Hardy-Weinberg equilibriumfor the peroxidase trait. Generate a Chi square value. c. Interpretthe Chi square value from part (b). If the population is not inHardy-Weinberg equilibrium, suggest a reason why.

Answer & Explanation Solved by verified expert

4.3 Ratings (909 Votes)

R2R2 P2 = 135

R2R3 2Pq = 44

R3R3 q2 = 11

Total = 190

R3R3 or q2 = 11 /190 = 0.05

Allelic frequency R3 or q = 0.22

P + q = 1

P = 1-0.22 = 0.78

P2 = 0.78 X 0.78 = 0.60Â Â Â Â Â Â 2pq = 2 X .78 X .22 = 0.34Â Â Â q2 = .22 X .22 = 0.04

Chi square test

	Observed	Expected	O-E	(O-E)2	(O-E)2/ E
R2R2	135	115	25	625	5.43
R2R3	44	64	-20	400	6.25
R3R3	11	9	2	4	0.44

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 12.12

Degree of freedom 1 at 95% chi square table valu = 3.814

12.12>3.814

we conclude that the genotype frequencies in this population are significantly different than what would be expected so this is not Hardy-Weinberg equilibrium.

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member