IQ scores in a large population have a normaldistribution with mean=100 and standard deviation=15. What is theprobability the sample mean for n=2 will be 121 or higher?
(I understand the z score equals 1.98,could you pleaseexplain to me how the final answer is equal to0.0239?thanks.)
Also, why do we use 1 and subtract 0.9761 to get 0.0239? Where does0.9761 come from?
