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In the rolling lab we measured the following conditions: R = 32.25; % roller radius (mm) Nr...

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Mechanical Engineering

In the rolling lab we measured the following conditions:

R = 32.25; % roller radius (mm)

Nr = 30; % roll rotational speed inrpm

A 8-pass flat rolling process was performed with one set ofworkpiece dimensional data of length l, width w, and thickness t,measured as below:

(with the first set of data for initial solder wire, and therests are the outlet dimensions of each pass)

l = [37.85 39.55 41.39 45.96 50.1959.83 79.64 127.5 260.0]; %length (mm)

w = [2.92 3.22 3.51 3.63 3.76 4.024.21 4.30 4.35]; %width (mm)

h = [2.92 2.38 2.059 1.672 1.470 1.1260.802 0.468 0.177]; %thickness (mm)

The total rolling time for each pass is:

t = [0.35 0.39 0.44 0.48 0.58 0.781.25 2.55];

Express the x-component of thevelocities of the roll vr(x) and the workpiece metalvm(x) as a function of x (where x is in rollingdirection and x=0 at the outlet section), for each pass, and plotvr(x) and vm(x) for each pass in onefigure

Answer & Explanation Solved by verified expert
4.5 Ratings (601 Votes)
Roller Radius R 3225 mmspeed N 30 rpmCircumference of roller PI2R 20263mmSince we    See Answer
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