In the Lesser Pahoa Kipuka Chicken population, the frequency of individuals born without bones is 1/2500...

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Biology

In the Lesser Pahoa Kipuka Chicken population, the frequency ofindividuals born without bones is 1/2500 individuals. Assuming thatonly half of the individuals homozygous recessivefor the \"boneless\" allele survive to reproductive maturity,determine both the selection coefficient (s) as well asthe mutation rate (Âµ) required to explain the persistence of theallele in the population due to mutation-selection balance.
s=_
Âµ =x 10^-4
Please show work.

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Natural selection is an important evolutionaryforce which comes in play due to differentialreproduction and survival of the individuals withdifferent genotypes and phenotypes in the population See Answer

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In the Lesser Pahoa Kipuka Chicken population, the frequency of individuals born without bones is 1/2500...

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Biology

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