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In the double-slit experiment of the figure below, the viewing screen is at distance D =...

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Physics

In the double-slit experiment of the figure below, the viewingscreen is at distance D = 4.00 m, point P lies atdistance y = 13.0 cm from the center of the pattern, theslit separation d is 4.50

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3.7 Ratings (347 Votes)

The wave length of light ? = 650nm

the seperation between slits d = 4.50?m

the distance between screen D = 4.0m

the postion of point P is y = 13cm

(a) The position of P in terms of phase difference

           ? = 2?/? dsin?

              =[ 2?/(650*10^-9)](4.5*10^-6)(y/D)

since for small angles sin? ? tan? = y/D

            = 0.0435*10^3 (13*10^-2/4)

            = 0.45? rad = 1.413 rad

(b) The ratio of intensity

           I/I0 = 4cos^2(?/2)

                  = 4cos^2(1.413/2)

                   =2.3
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