In procedure 2: suppose red light passes through a double slitand falls on a screen. In the diffraction pattern, the distancefrom the central maximum to the first maximum is 5 mm.

a) The distance from the first minimum (dark spot) to the secondminimum in the diffraction pattern is

between 7.5 mm and 10 mm

less than 2.5 mm    

more than 10 mm

between 2.5 mm and 5 mm

exactly 2.5 mm

between 5 mm and 7.5 mm

exactly 5 mm

exactly 7.5 mm

exactly 10 mm

b) Blue light has a higher frequency than red light. If you switchthe light falling on the double slit from red to blue

the distance between the maxima decreases, the number of maximaon the screen remains the same

the distance between the maxima increases, the number of maximaon the screen decreases    

the distance between the maxima increases, the number of maximaon the screen increases

the distance between the maxima decreases, the number of maximaon the screen decreases

the distance between the maxima remains the same, the number ofmaxima on the screen increases

the distance between the maxima remains the same, the number ofmaxima on the screen remains the same

the distance between the maxima decreases, the number of maximaon the screen increases

the distance between the maxima increases, the number of maximaon the screen remains the same

the distance between the maxima remains the same, the number ofmaxima on the screen decreases

c) Diffraction experiments are usually done with diffractiongratings (which have many slits) instead of a double slit. Theadvantage of the diffraction grating over a double slit (using thesame screen distance and slit width) is

there are many more maxima generated

it eliminates the central maximum    

all the maxima are farther apart

all the maxima are closer together

all the maxima are brighter

less light goes to the central maximum, and more to the othermaxima

d) For this question, there is more than one correct answer. To getthis question right, you must select all the correct answers!
You can change L (the distance from the slits to the screen), d(the distance between the slits) and λ (the wavelength ofthe light used). Which combination would double the distancebetween the maxima?

double L, leave λ and d unchanged

halve d, leave L and λ unchanged

halve L, halve d, halve λ

halve L, leave d and λ unchanged

double L, double λ, leave d unchanged

double λ, leave L and d unchanged

double d, halve L, leave λ unchanged

halve d, double λ, double L

double L, double λ, double d

halve d, double λ, leave L unchanged

double L, double d, leave λ unchanged

double L, halve d, leave λ unchanged

e) Suppose you are doing a double slit diffraction experiment withmonochromatic (single frequency) light. Suddenly the atmospherechanges from air to a gas with a higher index of refraction. Whatwill happen to the pattern?

the distance between the maxima will increase, the color of thelight will change to a lower frequency

the distance between the maxima will decrease, the color of thelight will remain the same    

the distance between the maxima will remain the same, the colorof the light will change to a higher frequency

the distance between the maxima will increase, the color of thelight will change to a higher frequency

the distance between the maxima will increase, the color of thelight will remain the same

the distance between the maxima will remain the same, the colorof the light will change to a lower frequency

the distance between the maxima will decrease, the color of thelight will change to a lower frequency

the distance between the maxima will remain the same, the colorof the light will remain the same

the distance between the maxima will decrease, the color of thelight will change to a higher frequency