In order to better understand one of the most important buffer systems in our body (the...

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Chemistry

In order to better understand one of the most important buffersystems in our body (the carbonic acid buffer system), you aretitrating 0.100 L of 0.100 M carbonic acid (shown below) with 0.500M NaOH.

What will the pH be when 23.0 mL of NaOH have been added? Pleasegive your answer to three decimal places.
pka 1: 6.05 pka2: 10.64

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4.3 Ratings (864 Votes)

moles of carbonic acid = 0.1 x 0.1 = 0.01

moles of NaOH = 0.5 x 23 / 1000 = 0.0115

pKa2 = 10.64

H2CO3 + OH- -----------------> HCO3- + H2O

0.01Â Â Â Â Â Â Â Â Â 0.0115Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â 0

Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â 0.0015Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.01Â Â Â Â Â Â Â Â Â 0.01

HCO3- + OH-Â Â ----------------> CO32- + H2O

0.01Â Â Â Â Â Â Â 0.0015Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â 0

0.0085Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.0015Â Â Â Â 0

here salt and acid remianed. so

pH = pKa2 + log [salt / acid]

Â Â Â Â = 10.64 + log [0.0015 / 0.0085]

Â Â Â Â = 9.887

pH = 9.887

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