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In February 1955, a paratrooper fell 370 m from an airplane without being able to open...

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Physics

In February 1955, a paratrooper fell 370 m from an airplanewithout being able to open his chute but happened to land in snow,suffering only minor injuries. Assume that his speed at impact was60 m/s (terminal speed), that his mass (including gear) was 71 kg,and that the magnitude of the force on him from the snow was at thesurvivable limit of 1.2

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4.5 Ratings (669 Votes)

Initial velocity, u = 0

Final velocity, v = 60 m/s

Mass of person along with gear, m = 71 kg

The force exerted by snow, F = 1.2 * 10^5 N = 120000 N

We have a formula F = ma

                      a = F/m = 120000/71 = 1690.14 m/s^2

Again we have a formula, 2as = (v^2 - u^2)

           from this, s = (v^2 - u^2)/2a = 1.065 m

The impulse on the person from the snow = mv - mu = mv - 0

                                                         = mv = 71 * 60 = 4260 kg m/s
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