Initial velocity, u = 0
Final velocity, v = 60 m/s
Mass of person along with gear, m = 71 kg
The force exerted by snow, F = 1.2 * 10^5 N = 120000 N
We have a formula F = ma
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a = F/m = 120000/71 = 1690.14 m/s^2
Again we have a formula, 2as = (v^2 - u^2)
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from this, s = (v^2 - u^2)/2a = 1.065 m
The impulse on the person from the snow = mv - mu = mv - 0
                                                       Â
= mv = 71 * 60 = 4260 kg m/s
