In a diagnostic x ray procedure, 4 8510 10 photonsare absorbed by tiss...

In a diagnostic x-ray procedure, 4.85Ã—1010 photons are absorbed by tissue with a mass of 0.575...

4.5 Ratings (853 Votes)

Number of protons are n =4.85*10^10

Wavelength of the each proton is Î»=2*10^-2nm=2*10^-11 m

Absorbed mass of the protons by tissue is m =0.575 kg

Energy absorbed by tissue with one proton is E =hC/Î»

here C is speed of light is =3*10^8 m/s

and 'h' is Plank's constant =6.625*10^-34 J.s

therefore

Energy absorbed by tissue with one proton is E =hC/Î»

=(6.625*10^-34)*(3*10^8)/(2*10^-11 )

=9.9375*10^-15 J

total energy absorbed by the tissue with the number of protons n =4.85 *10^10 is

E_total =nE

Â Â Â Â Â Â Â Â Â =4.85*10^10*9.9375*10^-15 J

Â Â Â Â Â Â Â Â =48.1968*10^-5 J

Equivalent dose D =energy absorbed/mass

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =48.1968*10^-5 J/0.575 kg

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =83.820*10^-5 J/kg

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =83.820*10^-5/0.01 rem

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =8382.05*10^-5 rem

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â since 1 rem =0.01 J/kg

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