In a 50Âµl reaction containing 0.25 pmol of a Michaelis enzyme with Km = 4.0 x...

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Biology

In a 50Âµl reaction containing 0.25 pmol of a Michaelis enzymewith Km = 4.0 x 10-7 M and substrate concentration of 2 x 10-7 M,product was formed at an initial velocity of 5.0 x 10-5 Mmin-1.
a. If the enzyme concentration is doubled to 0.5 pmol in thereaction, how much will the velocity increase? Showmathematically

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4.0 Ratings (430 Votes)

Ans. Reaction velocity is directly proportional to enzyme concertation in the reaction mixture. That is, increasing the enzyme concertation, while keeping other variables constant, also increases the reaction velocity by same factor.

So,

New (increased) reaction velocity = (New [enzyme] / Original [enzyme]) x Original Vo

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (0.50 pmol / 0.50 pmol) x (5.0 x 10^-5 M min^-1)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1.0 x 10^-4 M min^-1 Â Â

# Therefore, reaction velocity increases to 1.0 x 10^-4 M min^-1, i.e. 2 times that of the original reaction velocity.

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