Im stuck on questions (

Questions 2a-c (refer to a 0.250 kg pendulum, and thenanswer 2a-d)

An object suspended from a spring with a spring constantof 2.56 N/m vibrates with a frequency of 0.148 Hz. What is the mass of the object?

f=½(pi) x sqroot(k/m) 0.148Hz=½(pi) x sqroot(2.56N/m / m) 0.148 x 2(pi)= sqroot(2.56)/m 0.93 = sqroot(2.56Hz/m) 0.93^2=sqroot(2.56Hz/m) m=2.66/0.93^2 = 2.96kg The mass is 2.96kg

What is the acceleration of the object at a displacementof -0.120 m from the equilibrium position?

a=-wxsqroot(k/m)=sqroot(2.56/2.96=0.93rad/s^2) a=-0.93x(-0.12)=0.112m/s^2 The acceleration is 0.112m/s^2

Questions 2a-c refer to a 0.250 kgpendulum. What length of the pendulum would be needed to oscillateat the same frequency as the object in question 1?

What would be the restoring force on the pendulum at anangle of 6.24° from the equilibrium position?

The pendulum is pulled aside until it is 0.386 m aboveits lowest position and released. The pendulum is designed to emitsound waves at a frequency of 440 Hz; however, as it swings towardand away from an observer, the frequency appears to vary slightly.What would be the apparent frequency of the sound from the pendulumas it swings at its maximum speed toward an observer? Assume thespeed of sound is 345 m/s.