I'm not understanding quite how to do this type of problem. The problem states: What is...

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Chemistry

I'm not understanding quite how to do this type of problem. Theproblem states: What is the enthalpy change produced by thereaction of 50.0 g Fe2O3 with 50.0 g Al according to the equationbelow?

Fe2O3(s) + 2Al(s) => Al2O3(s) + 2Fe(s) Delta H = -851.5kJ

Please show me how to do this!

Answer & Explanation Solved by verified expert
4.2 Ratings (591 Votes)

moles of Fe2O3 = mass / molar mass of Fe2O3

                           = 50 / 159.69

                           = 0.313

moles of Al = 50 / 27 = 1.852                 

Fe2O3(s) +    2Al(s)   --------------------> Al2O3(s) + 2Fe(s)                                   Delta H = -851.5 kJ

   1 mol      2 mol                                   1 mol

0.313             1.852                           

here limiting reagent is Fe2O3 . so heat formed according to that.

1 mol Fe2O3 ------------------- delta H = - 851.5 kJ

0.313 mol Fe2O3 -------------   delta H = ??

heat formed = - 266.5 kJ


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