Ignoring activities, determine the molar solubility (S) of Zn(CN)2 in a solution with a pH =...

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Ignoring activities, determine the molar solubility (S) ofZn(CN)2 in a solution with a pH = 1.34. Ksp (Zn(CN)2) = 3.0 ×10-16; Ka (HCN) = 6.2 × 10-10.

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4.1 Ratings (437 Votes)

pH = 1.34

[H+] = 10^-pH = 10^-1.34 =0.0457 M

[H+] = [CN-] = 0.0457 M

Zn (CN)2 ---------------------------> Zn+2   + 2CN-

                                                    S             2S

                                                    S             0.0457

Ksp = [Zn+2] x (0.0457)^2

3.0x 10^-16 = S x (0.0457)^2

S = 1.44 x 10^-13 M

molar solubility = 1.44 x 10^-13 M


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