If you are given the followingsolids Na 3 PO 4 MW 163 94 g mol K 3 P...

If you are given the following solids: Na3PO4Â Â Â Â Â Â Â Â Â Â Â Â Â MW = 163.94 g/mol K3PO4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â MW = 212.26 g/mol Â Â NaH2PO4Â Â Â Â Â Â Â Â Â Â MW = 119.98 g/mol K2HPO4 Â Â Â Â Â Â Â Â Â Â Â MW...

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Chemistry

If you are given the followingsolids:
Na₃PO₄Â Â Â Â Â Â Â Â Â Â Â Â Â MW= 163.94 g/mol
K₃PO_{4Â Â Â Â Â}Â Â Â Â Â Â Â Â Â Â Â MW = 212.26 g/mol Â Â
NaH₂PO₄Â Â Â Â Â Â Â Â Â Â MW = 119.98 g/mol
K₂HPO₄Â Â Â Â Â Â Â Â Â Â Â MW = 174.17 g/mol
Na₂HPO₄Â Â Â Â Â Â Â Â Â Â MW = 141.96 g/mol
KH₂PO₄Â Â Â Â Â Â Â Â Â Â Â Â MW = 136.08 g/mol
Which compounds would you use toprepare your stock solutions? Why?

I picked KH2PO4 and K2HPO4 because potassium salts dissolve morereadily in H2O which would make the lab go more smoothly. I wouldlike to know if I'm missing any valuable pieces of information inthis answer.
If you are given deionized water,the solid you selected in the previous question and the followingvolumetric glassware:
100.00 ml volumetric flask(s)
250.00 ml volumetric flask(s)
Â Â 25.00 ml volumetrictransfer pipet(s)
Â Â 10.00 ml volumetrictransfer pipet(s)
Â Â Â Â 5.00 mlvolumetric transfer pipet(s)
Â Â Â Â Â Â Â Â Â Â Â Describe how you would prepare the required stock solutions (two).Your explanation should be detailed andquantitative.Â Â

Answer & Explanation Solved by verified expert

4.5 Ratings (841 Votes)

When making solutions for use in the biology lab controlling the concentration of solutes in the solution is often critical The control of the concentration of solutes in solutions used to culture cells can cause the cells die Inappropriate concentrations of solutes in solutions that contain bio molecules may cause the bio molecules to denature or aggregate thus making them inactive Concentrations of solutes can also affect the speed and types of chemical reactions that take place within a solution Dissolving solid solutes usually granules or powder in the solvent usually dH20 It cannot measure directly because we have no way to count atoms or molecules We use molecular weights of the molecules Weight of See Answer

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