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If the student uses 5.00 grams of (CH3)3CCO2H, how many grams of Mo(CO)6 will the student...

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Chemistry

If the student uses 5.00 grams of (CH3)3CCO2H, how many grams ofMo(CO)6 will the student need to react completely with the(CH3)3CCO2H.

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4.2 Ratings (851 Votes)

Answer – We are given the, mass of (CH3)3CCO2H = 5.00 g

So balanced reaction between Mo(CO)6 and (CH3)3CCO2H is as follow

2 Mo(CO)6 + 4 (CH3)3CCO2H ---> Mo2((CH3)3CCO2)4 + 12CO + 2H2

First we need to calculate the moles of (CH3)3CCO2H

Moles of (CH3)3CCO2H =5.00 g / 102.132 g.mol-1

                                        = 0.0490 moles

Now we need to calculate the moles of Mo(CO)6 using the mole ratio, so

From the balanced reaction

4 moles of (CH3)3CCO2H   = 2 moles of Mo(CO)6

So, 0.0490 moles of (CH3)3CCO2H   = ?

= 0.0245 moles of Mo(CO)6

So, mass of Mo(CO)6 = 0.0245 moles * 264.021 g/mol

                                    = 6.47 g

So, 6.47 grams of Mo(CO)6 will the student need to react completely with the (CH3)3CCO2H.
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