If the sollubility of sodiym acetate (Molar Mass = 82 g/mol) is 76 grams per 100...

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Chemistry

If the sollubility of sodiym acetate (Molar Mass = 82 g/mol) is76 grams per 100 grams of water, which of the following solutionswould be considered supersaturated (holding more than the normalmaxiym solution)? a.) 8.5 moles of sodium acetate dissolved in 1 Lof water, b.) 1.8 moles of sodiym acetate dissoved in 300 mL ofwater, c.) 5.5 moles of sodiym acetate dissolved in 500 mL ofwater, or d.) 1.2 moles of sodium acetate dissoved in 200 mL ofwater? I would like to understand how to calculate these kinds ofproblems. Please explain step by step how I should go about solvingthis so that I may learn how to do it for myself. There is ananswer on Chegg for this already but it doesn't appear to beaccurate nor does it clarify what is going on for \"understanding\"sake as I tried to solve it for myself using the method there andit was more confusing than helpful. So, I am asking it an effort togain a deeper and more accurate understanding.

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3.9 Ratings (431 Votes)

First calculate the solubility as mole per gram or mL of water and mole per L of water This will help you know if the solution are supersaturaded or not To calculate the moles we have moles MW moles 76 g82 gmol 093 moles100 g of water Now lets change the mass of water to volume the density of water will be assumed as 1 gmL so 100 g of water is 100 See Answer

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