If the Ka of a monoprotic weak acid is 8.2

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Chemistry

If the K_a of a monoprotic weak acid is 8.2

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Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â HA <-----> A-Â Â +Â Â Â Â Â Â Â H+
Initial:Â Â Â Â Â Â Â Â Â Â 0.28 Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0
Change:Â Â Â Â Â Â Â Â Â -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â Â Â Â Â Â Â Â +x
Final:Â Â Â Â Â Â Â Â Â Â 0.28-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â x x

Ka= x^2/0.28-x,

If 0.28 is greater than 100 Ka, we can approximate by ignoring the x subtracted from 0.28 and that is the case overhere.

Ka= x^2/0.28

8.2

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If the Ka of a monoprotic weak acid is 8.2

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If the Ka of a monoprotic weak acid is 8.2

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