If the Ka of a monoprotic weak acid is 3.8 × 10-6, what is the pH...

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Chemistry

If the Ka of a monoprotic weak acid is 3.8 × 10-6, what is thepH of a 0.11 M solution of this acid?

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4.4 Ratings (714 Votes)

costruct the ICE table

no need to cinsider H2O concentration since it is very large

            HA +         H2O       <----->      H3O+ + A-

I            0.11                                          0              0

C           -x                                              +x            +x

E            0.11-x                                      +x              +x

write the disociation expression

Ka = [H3O+][A-] / [HA]

3.8 × 10-6 = [x] [x] / [0.11-x]

3.8 × 10-6 = x2 / [0.11-x]

x2 + 3.8 × 10-6x - 0.418 * 10-6 = 0

solve the quadratic equation

x = 0.000644 = [H3O+]

pH = -log[H3O+]

= -log [0.000644]

= 3.19


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