If the first aa of a tripeptide is Met (AUG) followed by Ile (AUC) and Pro...

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Biology

If the first aa of a tripeptide is Met (AUG) followed by Ile(AUC) and Pro (CCU), the order of codons in the mRNA for thetripeptide should read
AUGAUGILECCUUAGÂ Â Â Â Â Â Â c.AUGILECCUU_{Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â}
AUGILECCUUAGÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â d. AUGILECCUUAGUAG
The first base of the codon is U, the number of codonsbeginning with U is
4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â b. 8_{Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â} c.12Â Â Â Â Â Â Â Â Â Â Â Â d. 16
Â Â Â A codon for Ile is AUC, therefore itsanticodon is
GAUÂ Â Â Â Â Â Â Â Â Â Â Â Â Â b.CUA_{Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â}c. UAGÂ Â Â Â Â Â Â Â Â Â d. UGA
Â Â The folding of tRNA has contributions from the
the TYC and the D arms together
the TYC alone
the TYC, anticodon and D arms
the TYC, aminoacyl, anticodon and D arms
Â Â Protein synthesis in bacteria is faster than inanimal cells because
transport of mRNA is faster through the smaller bacterialnucleus
there are more ribosomes in bacteria than in the animalcells
there are many nuclei in the bacteria making more mRNA
the mRNA of bacteria goes directly to the ribosome from thepolymerase

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Question 1 The correct answer is option a AUGAUGILECCUUAG Explanation First methionine called fmet is removed from most of the proteins So to retain methinine in the tripeptide there should be two methionine at the begining One will be removed and the other will be retained at the last there should be one stop codon so that protein synthesis stop at that See Answer

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