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If the coefficient of kinetic friction between tires and dry pavement is 0.90, what is the...

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Physics

If the coefficient of kinetic friction between tires and drypavement is 0.90, what is the shortest distance in which you canstop an automobile by locking the brakes when traveling at 22.9m/s?

On wet pavement, the coefficient of kinetic friction may be only0.25. How fast should you drive on wet pavement in order to be ableto stop in the same distance as in part A? (Note: Lockingthe brakes is notthe safest way to stop.)

If the coefficient of kinetic friction between tires and drypavement is 0.90, what is the shortest distance in which you canstop an automobile by locking the brakes when traveling at 22.9m/s?

Answer & Explanation Solved by verified expert
4.3 Ratings (636 Votes)

(a) Force of friction f = ?N = ?mg,

       where m is the massof the car.

       Aceleration,

                  a = f/m =?mg/m = ?g = 0.0 x9.8 = 8.82 m/s2

Theditance travelled, S before coming to rest (v = 0)

        S = (v2- u2)/2a

           =(0 - 22.9x22.9)/2x8.82

           =59.46 m

(b)   Acceleration, a = ?g = 0.25 x9.8 =2.45 m/s2

               u2 = v2 - 2a.S

                  = 0 - 2 x-2.45x59.46 = +291.354

  Initial velocity,

               u = ?291.354 = 17. 07 m/s
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