if S is non empty and it has a lower bound, then it has an...
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if S is non empty and it has a lower bound, then it has an infimum, inf S
Start of proof:
b<=s for all s in S
LB: {y in R:y<=S, for all s in S}
LB is bounded above by X and LB is non empty since b is in LB
Find supLB=infS, thats what needs to be completed
Answer & Explanation
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3.6 Ratings (356 Votes)
As you have not clearly mentioned the nature of S so I amanswering for two different cases with two different results1 S is a set of rational NumbersLets define S asHere S is non empty as 49 etc belong to SAlso it is
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