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If a solution containing 17.91 g17.91 g of mercury(II) perchlorate is allowed to react completely with...

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Chemistry

If a solution containing 17.91 g17.91 g of mercury(II)perchlorate is allowed to react completely with a solutioncontaining 5.102 g5.102 g of sodium dichromate, how many grams ofsolid precipitate will be formed?

mass:

gg

How many grams of the reactant in excess will remain after thereaction?

mass:

gg

Assuming complete precipitation, how many moles of each ionremain in solution? If an ion is no longer in solution, enter azero (0) for the number of moles.

Hg2+Hg2+:

molmol

ClO–4ClO4–:

molmol

Na+Na+:

molmol

Cr2O2−7Cr2O72−:

mol

Answer & Explanation Solved by verified expert
3.6 Ratings (683 Votes)
mass of solid precipitate formed 8113 gmass of reactant in excess 1013 gHg2 002536 molClO42 008966 molNa 003895 molCr2O72 0molExplanationBalanced equation HgClO42 Na2Cr2O7HgCr2O7 2 NaClO4Case 1 HgClO42 is the limitingreactantmass HgClO42    See Answer
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