If 1.6 mol cu metal reacts with a solution containing 3.9 mol AgNO3, what ions will...

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Chemistry

If 1.6 mol cu metal reacts with a solution containing 3.9 molAgNO3, what ions will be present at the end of the reaction?
Cu(s) + 2AgNO3(aq) --> Cu(NO3)2(aq) + Ag(s)
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4.3 Ratings (924 Votes)

Cu (s)Â Â +Â Â Â 2 AgNO3 (aq) ----------------------> Cu(NO3)2 (aq) + 2 Ag (s)

1 moleÂ Â Â Â Â Â Â Â Â Â Â 2 moleÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1 moleÂ Â Â Â Â Â Â Â Â Â Â 2 mole

1.6Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 3.9Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ?

Cu moles 1.6

AgNO3 moles = 3.9 /2 = 1.95

so AgNO3 is the excess reagent and Cu is limiting reagent

so total Cu will be consumed and Cu(NO3)2 formed = 1.6 moles

here now AgNO3 is left = 3.9 - 2 x 1.6 = 0.3

after reaction remaining species AgNO3 , Cu(NO3)2 and Ag

ions presentÂ Â :Â Â Ag⁺ , Cu²⁺ , NO₃^-

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