If 0.30 M HCOOH (weak acid) is prepared, what will be the hydronium ion concentration at...

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Chemistry

If 0.30 M HCOOH (weak acid) is prepared, what will be thehydronium ion concentration at equilibrium at 25

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The equilibrium chemical reaction is

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â HCOOH(aq) + H2O(l) <------------->Â Â HCOO-(aq) Â Â + Â Â H3O+(aq)

IÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.30 MÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0

CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +x

EÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.30-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +x

Ka = [HCOO-][H+] / [HCOOH]

1.70 x 10^-4 = x^2 / (0.30-x)

x^2 + (1.7 x 10^-4)x -(0.51 x 10^-4) = 0

Solving the quadratic equation, we get the roots

x = -0.007

x = +0.007

Thus, we use x = +0.007

Thus, the hydronium ion concentration = [H3O+] = x = 0.007 M

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