Identify the limiting reactant in the reaction of iron and chlorine to form FeCl3, if 2.21Ã—101 g of...

Free

70.2K

Verified Solution

Question

Chemistry

Identify the limiting reactant in the reaction ofiron and chlorine to formFeCl₃, if2.21Ã—10¹ g of Fe and3.59Ã—10¹ g ofCl₂ are combined. Determine the amount(in grams) of excess reactant that remains after the reaction iscomplete.

Formula of limiting reactant =

Amount of excess reactant remaining =___ g

Answer & Explanation Solved by verified expert

3.8 Ratings (648 Votes)

Â Â Â Â Â Â Â Â Â Â 2 FeÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +Â Â Â Â Â Â Â Â Â Â Â Â Â Â 3 Cl2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -------------->Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2 FeCl3

2.21Ã—10¹ g/ 55.85Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 3.59Ã—10¹ g/71

Â Â Â Â 0.3957molesÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.5056 moles

one mole Fe needs 1.5mole Cl2 for complete reaction

0.3957mole Fe needs 0.3957*1.5 = 0.59355moles of Cl2

So here the limiting reagent is Cl2 - chlorine

1.5 mole Cl2 needs one mole of Fe

0.5056moles of Cl2 needs 0.5056/1.5= 0.337 mole of Fe

So excess reagent = 0.3957-0.3370 = 0.0587moles of iron = 3.2784 grams

Weight = moles * molecular weight = 0.0587*55.85 = 3.2784grams

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member