I need part 1, 2, and 3 answered please just google PhET Massesand Springs Simulations Lab and click the first link. The previewof the lab should be in a box click the arrow/play button in thebox and the lab will open

2. Vectors At the base of your screen select ‘Vectors’. Thishelps in visualizing all vectors at play in oscillation. Select‘Displacement’, ‘Mass Equilibrium’, ‘Velocity’, ‘Acceleration’,‘Gravity’ and ‘Spring’. For first run leave Gravity as Earth.Attach 250g mass and observe vectors during oscillation.

(a) At which point is velocity minimum or zero?

(b) At which point is velocity maximum?

(c) At which point is acceleration zero?

(d) At which point is acceleration maximum?

(e) Is Gravity ever zero?

(f) Is spring force ever zero? When?

(g) What happens when Spring constant is increased?

(h) What happens when Gravity is changed to: (1) Moon (2)Jupiter (3) Planet X

(i) Determine value for gravity on Planet X.

3. Lab

At the base of your screen click on ‘Lab’.

Check boxes at top right corner for ‘Natural Length’ and‘Equilibrium Position’. Select ruler and stopwatch for linear andtime measure respectively.

Set Spring Constant and Damping such that Spring Constant isgreater than Damping. Select known 100g mass and attach it toSpring. Adjust mass measure to value greater than 250g.

Press red stop button at the side of Spring to stoposcillations.

1. Measure and record value for extension of Spring massattached.

Pull mass downward away from itsequilibrium position for an extension between 10 cm and 20 cm andrelease to begin oscillations.

1. Use stopwatch to time for ten (10) oscillations. Do two timetrials and get average of these two runs.
2. Determine periodic time, T
3. Calculate Spring Constant.
4. Determine energy of spring at the top of oscillation.
5. Determine energy of spring at equilibrium position.
6. Determine energy of spring at the lowest point inoscillation.
7. Determine total energy of system
8. Show that work done on spring is equal to change in springpotential energy: mg∆h = 1/2K(x2) 2 - 1/2K(x1) 2

What can be concluded from the results?