SF4 vapor at 650 torr and 100 C?
Vapour pressure of SF4 = 650
torr                             Â
(1atm = 760 Torr)
                                       Â
= 0.855atm
T = 100C = 373K ( c+ 273 = K)
fro ideal gas equation
PV=nRT
n = no of moles of gas = wt/mwt
PV = WtRT/Mwt
PMwt = (w/v)RT
(w/v) = density = d
d = P*Mwt / RT
p = pressure = 0.855atm
R = ideal gas constant = 0.0821
l.atm.k-1.mol-1
molarmass of SF4 = M.Wt = 108.1 gm/mole
density = (0.855*108.1)/(0.0821*373)
       = 3.02
gram/l
       = 0.00302
gram/ml
