I can't figure out how to create the decision tree with the sending a messaged situation! The...

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I can't figure out how to create the decision tree with thesending a messaged situation!

The crew of Endurance can visit two planets (Mann’s andEdmunds’). They can choose to visit neither planets, one of the twoplanets, or both planets. The characteristics of Mann’s planet arebelow:

• 30% chance of finding a perfectly habitable planet

• can support all of Earth’s current population if it is

• can support none of Earth’s population if it is not

And the characteristics of Edmunds’ planet are below:

• 50% chance of finding a perfectly habitable planet

• can support 50% of Earth’s current population if it is(because it is not as large as Mann’s planet)

• can support 20% of Earth’s current population if it is not(because it is still partially habitable)

The crew also needs to decide when to send a message to Earth tolet them know which planet to migrate to. The possible outcomes forthe different time steps of when they send that message arebelow:

• If they send the message before visiting both planets, none ofthe Earth’s population would have perished on Earth beforereceiving that message.

• If they send the message after visiting only one planet(either one), 10% of the Earth’s population would have perished onEarth before receiving that message.

• If they send the message after visiting both planets, 25% ofthe Earth’s population would have perished on Earth beforereceiving that message.

What should the crew do to save as many of Earth’s population aspossible? Specifically, which planet or planets should they visit,if any and in what order, and when should they send the message toEarth? Draw a decision tree to solve this problem.

Answer & Explanation Solved by verified expert
3.8 Ratings (368 Votes)
Start with No of planets to be visited 0 1 or 2 In case of 0 calculated expected survival In case of 1 segment the tree further Which planet to visit Manns Calculate the survival probability or in case of Edmunds    See Answer
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