I am stumped on these problems and homework question, please could I get the answers to...

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I am stumped on these problems and homework question, pleasecould I get the answers to the questions below from an expert.Thank you

5). Suppose that two population proportions are being comparedto test weather there is any difference between them. Assume thatthe test statistic has been calculated to be z= 2.21. Find thep-value for this situation?   a). p-value = 0.4864 b).p-value = 0.0272 c). p-value = 0.9728 d). p-value = 0.0136.

8). If you are given the following results of apaired-difference test. = -4.6 sd = 0.25 n = 16 Construct a 99percent confidence interval estimate for the paired difference inmean values?   a) - 3.141___-2.812 b) -5.241____-4.971c). -4.784___-4.416 d). -2.912____-2.718

16). Given a population in which the probability of success isp= 0.20, if a sample of 500 items is taken, than calculate theprobability the proportion of successes in the sample will bebetween 0.18 and 0.23 if the sample size is 200?   a). 0.8712 b). 0.8911 c). 0.7121 d). 0.6165

17). Construct a 98% confidence interval estimate for thepopulation mean given the following values?    a).(117.46, 122.54) b). (113.67, 126.33) c). (113.41, 126.59) d).(113.13, 126.87).

23). If a distribution for a quantitative variable is thought tobe nearly symmetric with very little variation, and a box andwhisker plot is created for this distribution, which of thefollowing is true? a). The box will be quite wide but the whiskerwill be very short b). The upper whisker will be much longer thanthe lower whisker. c). The whiskers should be about half as long asthe box is wide d). The left and right-hand edges of the box willbe approximately equal distance from the median.

24). A randomly selected customer support wait time (from anormal distribution) is calculated to be 1.8 standard deviationsabove its mean. What is the probability that another randomlyselected customer wait time from the distribution will be less than1.8 standard deviations from the mean? a). 0.9641 b).0.9976 c).0.9281 d). 0.0359

25). The advantage of using the interquartile range versus therange as a measure of variation is?   a). it is easier tocompute b). it gives a value that is closer to the true variation.c). it is less affected by extremes in the data d). it utilizes allthe data in its computation.

34). Given a population where the proportion of items with adesired attribute is p=0,25, if a sample of 400 is taken, what isthe probability the proportion of successes in the sample will begreater than 0.22? a). 0.9162 b). 0.8412 c). 0.8812 d). 0.7141

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