A) Rate = k [A]1[B]1
            Â
AÂ Â Â Â
+Â Â Â Â Â Â Â Â
BÂ Â Â Â Â --> C
Initial   Â
a             Â
b           Â
0
Final   Â
a-x          Â
b-x        x
dx / dt = rae of formation of C= K(a-x)(b-x)
dx/(a-x) (b-x) = Kdt
On integrating we will obtain
K = 1/ t(b-a) } lna(b-x) / ln b(a-x)
So if we know the rate constant and initial concentration we can
find the value of x an hence the unreacted concentration of A
B) rate = k[A]0[B]0
so dx/ dt = K[A]0[B]0
or dx = dt
On integrating we will have
K =x/t
So if we know the value of K we can calculate the value of x at
time 2 hours
